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Here is a code block:
print("hello world!")
Here is an inline code: uv tool install bloops Here's an Asymptote diagram:
some caption text
Here's a cute diagram from my IMO 2023 G4 solve. One of my favorite problems ever. :)
cute diagram from IMO 2023 P2
Time for some math! $$ \begin{align*} M_X(t) &= E[e^{tX}] \\ &= \int_{-\infty}^{\infty} e^{tx} \frac{1}{\sigma \sqrt{2\pi}} \exp\left( -\frac{(x-\mu)^2}{2\sigma^2} \right) dx \\ &= \int_{-\infty}^{\infty} \frac{1}{\sigma \sqrt{2\pi}} \exp\left( tx - \frac{(x-\mu)^2}{2\sigma^2} \right) dx \\ &= \int_{-\infty}^{\infty} \frac{1}{\sigma \sqrt{2\pi}} \exp\left( \frac{2\sigma^2 tx - (x^2 - 2\mu x + \mu^2)}{2\sigma^2} \right) dx \\ &= \int_{-\infty}^{\infty} \frac{1}{\sigma \sqrt{2\pi}} \exp\left( \frac{-x^2 + 2(\mu + \sigma^2 t)x - \mu^2}{2\sigma^2} \right) dx \\ &= \int_{-\infty}^{\infty} \frac{1}{\sigma \sqrt{2\pi}} \exp\left( \frac{-[x - (\mu + \sigma^2 t)]^2 + 2\mu\sigma^2 t + \sigma^4 t^2}{2\sigma^2} \right) dx \\ &= \exp\left( \frac{2\mu\sigma^2 t + \sigma^4 t^2}{2\sigma^2} \right) \int_{-\infty}^{\infty} \frac{1}{\sigma \sqrt{2\pi}} \exp\left( -\frac{[x - (\mu + \sigma^2 t)]^2}{2\sigma^2} \right) dx \\ &= \exp\left( \mu t + \frac{1}{2}\sigma^2 t^2 \right) \cdot 1 \\ &= e^{\mu t + \frac{1}{2}\sigma^2 t^2} \end{align*} $$

To confuse your enemy, you must first confuse yourself

sun tzu
Time for some math boxes!
Proposition (meow). some theorem statement.
Lemma (trivial lemma). Consider the following operation on an arbitrary positive integer: Prove that this process will eventually reach the number 1, regardless of which positive integer is chosen initially.
The proof is hidden inside this block.
Proof. Left as an exercise to the reader Skipped, too easy.□