Brackets
========

Use c-style brackets instead of indentation. This is an encoding, you
can also import this module in sites.py, it will register the encoding
on import.

To install:

::

    pip install brackets

to use this, add the magic encoding comment to your source file:

::

    # coding: brackets

Then you can import it directly (obvsly brackets should be imported
first), or if you added the encoding to your sites.py, you can use idle
to view the decoded file.

Currently just works for "if\|elif\|else\|for\|while\|def\|with"
statements. It's also possible to mix indentation and brackets. You can
do that, but it is not recommended. This started as a code, a hobby
project in 2014, but now I started working on it again.

You can also decode brackets literals:

::

    import brackets
    a = b'brackets code'
    a.decode('brackets')

To know how to code with brackets examine the examples provided here.
There's no warranty. There might be parsing errors, report if there are
any, feel free to make a pull request.

What this can do?
-----------------

This will convert:

::

    if(1 in {1,2,3}){
        print(5)
        for(x in c){
            print(c)
        }
    }

To this:

::

    if(1 in {1,2,3}):
        print(5)
        for x in c:
            print(c)

It works for messy code too. see how this can work on this one-line
code:

::

    def fib(n){if(n in 0){return n}else{return fib(n-1)+fib(n-2)}}

The result from the previous is:

::

    def fib(n):
        if(n in 0):
            return n
        else:
            return fib(n-1)+fib(n-2)

using ; is supported:

::

    import io; def fib(n){/* code */} ; print("hello");

You can also write anonymous functions like this:

::

    print([def(x, y) {return x + y}(x, y) for x in range(0, 5) for y in range(-5, 0)])
    print([def(x) { if(x in [0, 1]) {return x}; while (x < 100) { x = x ** 2} return x}(x) for x in range(0, 10)])

Not necessarily in one line:

::

    print([def(x) {
            if(x in [0, 1]) {
              return x
            };
            while (x < 100) {
              x = x ** 2
            };
            return x
          }(x) for x in range(0, 10)])

Note that this anonymous function isn't Python lambda, they're real
functions, without limitations of lambda.

Project Info
------------

Github project page: https://github.com/pooya-eghbali/brackets Mail me
at: persian.writer [at] Gmail.com
